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D( y )
y-2 = 0
y-2 = 0
y-2 = 0
y-2 = 0 // + 2
y = 2
y in (-oo:2) U (2:+oo)
t_2 = 0
(3*y^3-5*y^2+2*y-1)/(y-2)+t_2 = 0
(3*y^3-5*y^2+2*y-1)/(y-2)+(t_2*(y-2))/(y-2) = 0
t_2*(y-2)+3*y^3-5*y^2+2*y-1 = 0
t_2*y-2*t_2+3*y^3-5*y^2+2*y-1 = 0
t_2*y-2*t_2+3*y^3-5*y^2+2*y-1 = 0
t_2*y-2*t_2+3*y^3-5*y^2+2*y-1
y*(3*y^2+2)+t_2*y-2*t_2-5*y^2-1
y*(t_2-5*y)+y*(3*y^2+2)-2*t_2-1
y*(t_2-5*y)-1*(2*t_2+1)+y*(3*y^2+2)
y*(t_2+3*y^2-5*y+2)-1*(2*t_2+1)
0*(t_2+3*y^2-5*y+2)
(0*(t_2+3*y^2-5*y+2))/(y-2) = 0
(0*(t_2+3*y^2-5*y+2))/(y-2) = 0 // * y-2
0*(t_2+3*y^2-5*y+2) = 0
t_2+3*y^2-5*y+2 = 0
DELTA = (-5)^2-(3*4*(t_2+2))
DELTA = 25-12*(t_2+2)
25-12*(t_2+2) = 0
25-12*(t_2+2) = 0
1-12*t_2 = 0
1-12*t_2 = 0
1-12*t_2 = 0 // - 1
-12*t_2 = -1 // : -12
t_2 = -1/(-12)
t_2 = 1/12
DELTA = 0 <=> t_4 = 1/12
y = 5/(2*3) i t_2 = 1/12
y = 5/6 i t_2 = 1/12
( y = ((25-12*(t_2+2))^(1/2)+5)/(2*3) or y = (5-(25-12*(t_2+2))^(1/2))/(2*3) ) i t_2 > 1/12
( y = ((25-12*(t_2+2))^(1/2)+5)/6 or y = (5-(25-12*(t_2+2))^(1/2))/6 ) i t_2 > 1/12
t_2-1/12 > 0
t_2-1/12 > 0 // + 1/12
t_2 > 1/12
y in { 5/6, ((25-12*(0+2))^(1/2)+5)/6, (5-(25-12*(0+2))^(1/2))/6 }
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